A random variable `X` has its range `{-1,0,1}`. If its mean is `0.2` and `P(X=0)=0.2` ,then `P(X=1)=`

A random variable X takes the value -1,0,1. It's mean is 0.6. If P(X=0)=0.2 then P(X=1)=

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=

A random variate X takes the values 0,1,2,3 and its mean is 1.3. If P(X=3)=2P(X=1) and P(X=2)=0.3, then P(X=0) is equal to

A random variable X takes the values 0,1 and 2 .If P(X=1)=P(X=2) and P(X=0)=0.4 ,then the mean value of the random variable X is

A random variable X has its range (1 2 3} If P(X=1)=alpha P(X=2)=beta, p(X=3)=(1)/(6) and the mean is (5)/(3) then alpha , beta=

If a random variable x assumes the values 0,1 and 2 with probabilities 0.30,0.50 and 0.20, then its expected value is (A) 1.50(B)3(C)0.90 (D) 1

If the random variable 1 follows a Poisson distribution with mean 3 then P(X=0) is

Let x be a random variable such that the probability function of a distribution is given by P(X=0) =1/2 , P(X = J ) = 1/(3^j) ( j = 1,2,3 ,…..,,oo) then the mean of the distribution and P(X is positive and even) respectively are:

A random variable X has the follwing probability distribution: Find P( 0 lt X lt 4)

Given a random variable that takes values X = {0, 1, 2} and has a probability distribution, P(0)= (1)/(4),P(1) = (1)/(2), P(2) = (1)/(4) . Then find the variance of X.