Let `I_(n)=inttan^(n)xdx , n gt 1`. `I_(4)_I_(6)=atan^(5)x+bx^(5)+C` , where C is a constant of integration , then the ordered pair ( a , b) is equal to

Let I_(n)=int tan^(n)xdx,(n>1). If I_(4)+I_(6)=a tan^(5)x+bx^(5)+C, where C is a constant of integration,then the ordered pair (a,b) is equal to :

Let I_(n)=int tan^(n)xdx,(n>1) If I_(4)+I_(6)=a tan^(5)x+bx^(5)+C, where C is a a constant of integration,then the ordered pair (a,b) is equal to : (1)((5)/(1),-1)(2)(-(1)/(5,0))(3)(-(1)/(5),1)(4)((1)/(5),0)

LetI _(n)=int tan^(n)xdx,(n>1). If I_(4)+I_(6)=a tan^(5)x+bx^(5)+c where c is a constant of integration then thee ordered pair (a,b) is

Let I_(n)=inttan^nxdx,(ngt1)*I_(4)+I_(6)=atan^5x+bx^5+c , where c is constant of integration, then the ordered pair (a,b) is equal to

If int (2x + 5 )/(sqrt(7 - 6 x - x ^ 2 )) dx = A sqrt (7 - 6x - x ^ 2 ) + B sin ^ ( -1) (( x + 3 )/( 4 ) ) + C (Where C is a constant of integration), then the ordered pair (A, B) is equal to :

If I_(n)=int x^(n)e^(x)dx, then I_(5)+5I_(4)=

If I_(n)-int(lnx)^(n)dx, then I_(10)+10I_(9) is equal to (where C is the constant of integration)

What is int sec^(n)x tan xdx equal to ? Where 'c' is a constant of integration

let I_(n)=int_(0)^((pi)/(4))tan^(n)xdx,n>1

If I_(n)=int cos^(n)xdx, then (n+1)I_(n+1)-nI_(n-1)=