The length of the sides of the square which can be made by four perpendicular tangents to the ellipse `x^2/7+(2y^2)/11=1`, is

The length of the sides of the square which can be made by four prpendicular tangents to the ellipse (x^(2))/(7)+(2y^(2))/(11)=1, is

Two perpendicular tangents drawn to the ellipse (x^(2))/(25)+(y^(2))/(16)=1 intersect on the curve.

The locus of the point of intersection of perpendicular tangents to the ellipse (x - 1)^2/16 + (y-2)^2/9= 1 is

Prove that the minimum length of the intercept made by the axes on the tangents to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is equal to (a+b)

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

The locus of the foot of the perpendicular drawn from the centre on any tangent to the ellipse x^2/25+y^2/16=1 is:

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

The locus of point intersection of perpendicular tangents of ellipse ((x-1)^(2))/(16)+((y-1)^(2))/(9)=1 is