The normal at `(2,(3)/(2))` to the ellipse `x^2/16+y^(2)/(3)=1` touches a parabola,whose equation is
1) `y^2=-104x" "` 2) `y^2=14x`
3) `y^(2)=-26x" "` 4) `y^2=-14x`

If the line y=x+sqrt(3) touches the ellipse (x^(2))/(4)+(y^(2))/(1)=1 then the point of contact is

The line 3x+5y=k touches the ellipse 16x^(2)+25y^(2)=400 ,if k is

If the line y=x+c touches the ellipse 2x^(2)+3y^(2)=1 then c=

If x+y=k is a normal to the parabola y^(2)=12x then it touches the parabola y^(2)=px then

If x+y=k is a normal to the parabola y^(2)=12x, then it touches the parabola y^(2)=px then |P| =

The value of |C| for which the line y=3x+c touches the ellipse 16x^2+y^2=16 is:

Find the equation of tangent to the ellipse 3x^2+y^2+2y=0 which are perpendiculor to the line 4x-2y=1 .

An ellipse is drawn by taking a diameter of the circle (x""""1)^2+""y^2=""1 as its semiminor axis and a diameter of the circle x^2+""(y""""2)^2=""4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) 4x^2+""y^2=""4 (2) x^2+""4y^2=""8 (3) 4x^2+""y^2=""8 (4) x^2+""4y^2=""16

If a tangent of slope (1)/(3) of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a>b) is normal to the circle x^(2)+y^(2)+2x+2y+1=0 then

The solutions of the equations x+2y+3z=14,3x+y+2z=11,2x+3y+z=11