In a binomial distribution mean =`(11)/(4)` and variance =`(15)/(16)`, then the probability of success is

For a binomial distribution, if mean is 8 and variance is 6, then the probability of atleast 1 success is.

In a binomial distribution , prove that mean gt variance

The mean and the variance of a binomial distribution are 4 and 2 respectively. Then, the probability of 2 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.Then the probability of 3 successes is

In a binomial distribution, mean is 3 and standard deviation is 3/2 , then the probability function is

Mean and variance of a binomial distribution are 4 and 2 respectively . Then probability of 3 successes is

The mean and the variance of a binomial distribution are 4 and 2 respectively.then, the probabitly of 2 , successes is

In a binomial distribution, the mean is 4 and variance is 3. Then its mode is