If a metal is exposed with light of wavelength `lambda,` the maximum kinetic energy produced is found to be 2 eV. When the same metal is exposed to a
wavelength `(lambda)/(5)` the maximum kinetic energy was found to be 14 eV. Find the value of work function (in eV).

When a metal is illuminated with light of frequency f, the maximum kinetic energy of the photoelectrons is 1.2 eV. When the frequency is increased by 50% the maximum kinetic energy increases to 4.2 eV. What is the threshold frequency for this metal?

Consider a metal exposed to light of wavelength 600nm. The maximum energy of the electrons doubles when light of wavelength 400nm is used. Find the work function in eV.

A radiation of wavelength lamda illuminates a metal and ejects photoelectrons of maximum kinetic energy of 1eV. Aother radiation of wavelength (lamda)/(3) , ejects photoelectrons of maximum kinetic energy of 4eV. What will be the work function of metal?

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

Maximum kinetic energy of photoelectrons emitted from a metal surface, when light of wavelength lambda is incident on it, is 1 eV. When a light of wavelength lambda/3 is incident on the surfaces, maximum kinetic energy becomes 4 times. The work function of the metal is

The work function of a metal is 3.4 eV. A light of wavelength 3000Å is incident on it. The maximum kinetic energy of the ejected electron will be :

The surface of a metal is illuminated with light of wavelength 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. What is the work function of the metal ? [ hC=1240 eV*nm ]

The photoelctric effect work function for a metal is 4.2 eV. If the stopping potential is 3V, find the threshold wavelength and the maximum kinetic energy of emitted electrons.