The path difference between two interfering waves at a point on the screen is `lambda // 6`, The ratio of intensity at this point and that at the central bright fringe will be (assume that intensity due to each slit is same)

The path of difference between two interfering waves at a point on the screen is (lambda)/(8) . The ratio of intensity at this point and that at the central fringe will be :

The path difference between two interfering waves of equal intensities at a point on the screen is lambda//4 . The ratio of intensity at this point and that at the central fringe will be

The path difference between two interfering waves at a point on screen is 70.5 tomes the wave length. The point is

The path difference between two interfering light waves meeting at a point on the screen is ((87)/(2))lamda . The band obtained at that point is

If path difference between two interfering waves is zero, then the point will be

In YDSE path difference at a point on screen is lambda/8 . Find ratio of intensity at this point with maximum intensity.

If path difference between two interfering waves arriving at a point is zero, then the point will

In Young’s double slit experiment, light from two identical sources are superimposing on a screen. The path difference between the two lights reaching at a point on the screen is frac{7 lambda}{4} . The ratio of intensity of fringe at this point with respect to the maximum intensity of the fringe is :

The path difference between two interfering waves at a point on screen is 171.5 times the wavelength if the path difference is 0.01029 cm find the wavelength.

In a Young's double slit experiment , the path difference at a certain point on the screen ,between two interfering waves is 1/8 th of wavelength.The ratio of the intensity at this point to that at the center of a bright fringe is close to :