Le the be a real valued functions satisfying `f(x+1) + f(x-1) = 2 f(x)` for all `x, y in R` and `f(0) = 0`, then for any `n in N`, f(n) =

Let f be a real valued function satisfying f(x+y)=f(x)+f(y) for all x, y in R and f(1)=2 . Then sum_(k=1)^(n)f(k)=

Let f be a real valued function satisfying f(x+y)=f(x)+f(y) for all x, y in R and f(1)=2 . Then sum_(k=1)^(n)f(k)=

Let f be a real valued function, satisfying f (x+y) =f (x) f (y) for all a,y in R Such that, f (1) =a. Then , f (x) =

Let f be a real valued function, satisfying f (x+y) =f (x) f (y) for all a,y in R Such that, f (1_ =a. Then , f (x) =

Let f be a real valued function satisfying f(x+y)=f(x)f(y) for all x, y in R such that f(1)=2 . Then , sum_(k=1)^(n) f(k)=

Let f be a real valued function satisfying f(x+y)=f(x)f(y) for all x, y in R such that f(1)=2 . Then , sum_(k=1)^(n) f(k)=

If f(x) is a real valued functions satisfying f(x+y) = f(x) +f(y) -yx -1 for all x, y in R such that f(1)=1 then the number of solutions of f(n) = n,n in N , is

If f(x) is a real valued functions satisfying f(x+y) = f(x) +f(y) -yx -1 for all x, y in R such that f(1)=1 then the number of solutions of f(n) = n,n in N , is

Let a real valued function f satisfy f(x + y) = f(x)f(y)AA x, y in R and f(0)!=0 Then g(x)=f(x)/(1+[f(x)]^2) is

Let f be a function satisfying f(x+y)=f(x) + f(y) for all x,y in R . If f (1)= k then f(n), n in N is equal to