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Solve : 2^x + 2^(x-1) + 2^(x-2) = 7^x + ...

Solve : `2^x + 2^(x-1) + 2^(x-2) = 7^x + 7^(x-1) + 7^(x-2)`

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.Number of solutions of equation 2^x + 2^(x-1) + 2^(x-2) = 7^x + 7^(x -1) + 7^(x-2) is

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Number of real roots of the equation 2^x=2^(x-1)+2^(x-2)=7^x+7^(x-1)+7^(x-2) is (A) 4 (B) 2 (C) 1 (D) 0

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