`(cosx)^(sinx)` का अवकलन `(sinx)^(cosx)` के सापेक्ष कीजिए ।

cosx{(cosx)/(1-sinx)+(1-sinx)/(cosx)}, is

cosx{(cosx)/(1-sinx)+(1-sinx)/(cosx)}, is

Differentiate (cosx)^(sinx) with respect to (sinx)^(cosx) .

Show that (1-cosx)/sinx = sinx/(1+cosx)

(cosx)/(1+sinx)+(1+sinx)/(cosx) is equal to: (cosx)/(1+sinx)+(1+sinx)/(cosx) किसके बराबर है:

"If "y=(sinx)^(cosx)+(cosx)^(sinx)", prove that "(dy)/(dx)=(sinx)^(cosx).[cot x cos x-sin x(log sinx)]+(cosx)^(sinx).[cosx(log cos x)-sinx tanx].

Evaluate int (cosx-sinx)dx/(sinx+cosx)

((sinx - cosx)/(sinx + cosx))

int (sinx-cosx)/(cosx+sinx)dx =