Find the pressure at a depth of 10 m in water in water if the atmspheric pressure is 100 kPa.
`[1Pa=1N//m^(2)][100Kpa10^(5)N//m^(2)=1atm.]`

Find the pressure at a depth of 10 m in water if the atmospheric pressure is 100kPa. [1Pa=1N//m^(2)] [100kPa=10^(5) Pa=10 ^(5) N//m^(2) =1 atm.]

Find the pressure at a depth of 10 m in water if tre atmospheric pressure is 100kPa. [1Pa=1N//m] [100kPa=10^(5) Pa=10 ^(5) N//m^(2) =1 atm.]

What is the pressure in an ocean at a depth of 1000 m, if the density of water is 1.024xx 10^(3) (kg)/m^(3) . Atmospheric pressure P. = 1.01 xx 10^(5) Pa.

An experimentally decided formula for relation between pressure and density of x a liquid is (P)/(P_("atm"))=(B+1)((d)/(d_("atm")))^(n)-B B and n are constant. P_("atm") is atmospheric pressure and d_("atm") is the density of liquid at that pressure. For water numerical values of B=3000 and n=7. Take atmospheric pressure=100kPa and density of water =10^(3) kg//m^(3) at atmospheric pressure. At what depth is the density of water increase by 0.001%.