If f(x) is a non - negative function such that the area bounded by `y=f(x),` x - axis and the lines x = 0 and `x=alpha` is `4alpha sin alpha+2` sq. Units
(`AA alpha in [0, pi]`), then the value of `f((pi)/(2))` is equal to

Let f(x) be a continuous and positive function, such that the area bounded by y=f(x), x - axis and the lines x^(2)=2ax is 6a^(2)+sina(AA a gt 0) sq. units. If f(pi)=kpi , then the value of k is equal to

Let f(x) be a continuous and positive function, such that the area bounded by y=f(x), x - axis and the lines x^(2)=2ax is 6a^(2)+sina(AA a gt 0) sq. units. If f(pi)=kpi , then the value of k is equal to

Let f (x) be a continous function such that the area bounded by the curve y =f (x) x-axis and the lines x=0 and x =a is (a ^(2))/( 2) + (a)/(2) sin a+ pi/2 cos a, then f ((pi)/(2)) is

Let f(x)>0 be a continuous function such that the area bounded by the curve y=f(x),x -axis and the lines x=0 and x=lambda is + (lambda^(2))/(2)+cos^(2)lambda .Then f((pi)/(4)) is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), x-axis and the ordinates x=pi/4 and x=beta gt pi/4 is : (beta sin beta + pi/4 cos beta +sqrt2beta) . Then f(pi/2) is :

Let f(x) be non- negative continuous function such that the area bounded by the curve y=f(x) , x- axis and the ordinates x= (pi)/(4) and x = beta ( beta gt (pi)/(4)) is beta sin beta + (pi)/(4) cos beta + sqrt(2) beta . Then the value of f((pi)/(2)) is-

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x) , x-axis and the ordinates x=(pi)/(4) and x = bet gt (pi)/(4) is beta sin beta +(pi)/(4) cos beta +sqrt(2) beta then f((pi)/(2))=

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=(pi)/(4) and x=betagt(pi)/(4)" is "beta sin beta +(pi)/(4)cos beta +sqrt(2)beta. Then f'((pi)/(2)) is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=(pi)/(4) and x=betagt(pi)/(4)" is "beta sin beta +(pi)/(4)cos beta +sqrt(2)beta. Then f'((pi)/(2)) is

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=(pi)/(4) and x=betagt(pi)/(4)" is "beta sin beta +(pi)/(4)cos beta +sqrt(2)beta. Then f'((pi)/(2)) is