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If R = {{2,a),(3,c),(9,b),(7,a), (8,a), ...

If `R = {{2,a),(3,c),(9,b),(7,a), (8,a), (1,d)}`, then `R^(-1)` is equal to

A

{(a,2),(a,7),(a,8),(b,9),(c,3),(d,1)}

B

{(a,2),(b,9),(c,2),(d,1)}

C

{(a,7),(a,8),(c,2),(d,1)}

D

{(a,2),(b,9),(c,3),(d,1)}

Text Solution

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The correct Answer is:
To find the inverse of the relation \( R \), we need to reverse the ordered pairs in the relation. The relation \( R \) is given as: \[ R = \{(2, a), (3, c), (9, b), (7, a), (8, a), (1, d)\} \] ### Step-by-Step Solution: 1. **Identify the Ordered Pairs**: The relation \( R \) consists of the following ordered pairs: - \( (2, a) \) - \( (3, c) \) - \( (9, b) \) - \( (7, a) \) - \( (8, a) \) - \( (1, d) \) 2. **Reverse Each Ordered Pair**: To find the inverse relation \( R^{-1} \), we will reverse each of the ordered pairs: - The pair \( (2, a) \) becomes \( (a, 2) \) - The pair \( (3, c) \) becomes \( (c, 3) \) - The pair \( (9, b) \) becomes \( (b, 9) \) - The pair \( (7, a) \) becomes \( (a, 7) \) - The pair \( (8, a) \) becomes \( (a, 8) \) - The pair \( (1, d) \) becomes \( (d, 1) \) 3. **Combine the Reversed Pairs**: Now, we will combine all the reversed pairs into the inverse relation: \[ R^{-1} = \{(a, 2), (c, 3), (b, 9), (a, 7), (a, 8), (d, 1)\} \] 4. **Final Result**: Thus, the inverse of the relation \( R \) is: \[ R^{-1} = \{(a, 2), (c, 3), (b, 9), (a, 7), (a, 8), (d, 1)\} \]
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