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Let f: R -{0} to R be defined by f(x) =x...

Let `f: R -{0} to R` be defined by `f(x) =x + 1/x`, then range of
`g(x) = (f(x))^(4) - f(x^(4)) - 4(f(x))^(2)`, is

A

`R-(2)`

B

`{2}`

C

`{-2}`

D

`R - {2}`

Text Solution

AI Generated Solution

The correct Answer is:
To find the range of the function \( g(x) = (f(x))^4 - f(x^4) - 4(f(x))^2 \), where \( f(x) = x + \frac{1}{x} \), we will follow these steps: ### Step 1: Understand the function \( f(x) \) The function \( f(x) = x + \frac{1}{x} \) is defined for all real numbers \( x \) except \( x = 0 \). ### Step 2: Determine the range of \( f(x) \) To find the range of \( f(x) \), we can analyze its behavior. 1. **Finding the minimum value of \( f(x) \)**: - We can use the AM-GM inequality: \[ x + \frac{1}{x} \geq 2 \quad \text{for } x > 0 \] and \[ x + \frac{1}{x} \leq -2 \quad \text{for } x < 0 \] - Thus, the minimum value of \( f(x) \) is \( 2 \) when \( x = 1 \) and \( -2 \) when \( x = -1 \). 2. **Conclusion about the range of \( f(x) \)**: - Therefore, the range of \( f(x) \) is \( (-\infty, -2] \cup [2, \infty) \). ### Step 3: Find \( f(x^4) \) Next, we need to compute \( f(x^4) \): \[ f(x^4) = x^4 + \frac{1}{x^4} \] ### Step 4: Express \( g(x) \) Now we can substitute \( f(x) \) and \( f(x^4) \) into \( g(x) \): \[ g(x) = (f(x))^4 - f(x^4) - 4(f(x))^2 \] Substituting \( f(x) = x + \frac{1}{x} \): \[ g(x) = \left(x + \frac{1}{x}\right)^4 - \left(x^4 + \frac{1}{x^4}\right) - 4\left(x + \frac{1}{x}\right)^2 \] ### Step 5: Simplify \( g(x) \) 1. **Calculate \( (f(x))^2 \)**: \[ (f(x))^2 = \left(x + \frac{1}{x}\right)^2 = x^2 + 2 + \frac{1}{x^2} \] 2. **Calculate \( (f(x))^4 \)**: \[ (f(x))^4 = \left(x^2 + 2 + \frac{1}{x^2}\right)^2 \] 3. **Calculate \( f(x^4) \)**: \[ f(x^4) = x^4 + \frac{1}{x^4} \] ### Step 6: Substitute and simplify After substituting and simplifying, we find that: \[ g(x) = -2 \] ### Step 7: Determine the range of \( g(x) \) Since \( g(x) \) simplifies to the constant value \( -2 \), the range of \( g(x) \) is simply: \[ \text{Range of } g(x) = \{-2\} \] ### Final Answer: The range of \( g(x) \) is \( \{-2\} \). ---
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MCGROW HILL PUBLICATION-SETS, RELATIONS AND FUNCTIONS-EXERCISE ( LEVEL 1 (SINGLE CORRECT ANSWER TYPE QUESTIONS ))
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  16. Let f: R -{0} to R be defined by f(x) =x + 1/x, then range of g(x) =...

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