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Let f:[0, infty) to [0, infty) and g: [0...

Let `f:[0, infty) to [0, infty)` and `g: [0, infty) to [0, infty)` be two functions such that f is non-increasing and g is non-decreasing. Let `h(x) = g(f(x)) AA x in [0, infty)`. If `h(0) =0`, then h(2020) is equal to

A

0

B

1

C

1010

D

2020

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the functions \( f \) and \( g \) and their properties, as well as the composite function \( h(x) = g(f(x)) \). ### Step-by-Step Solution: 1. **Understanding the Functions:** - The function \( f: [0, \infty) \to [0, \infty) \) is non-increasing. This means that for any \( x_1 < x_2 \), we have \( f(x_1) \geq f(x_2) \). - The function \( g: [0, \infty) \to [0, \infty) \) is non-decreasing. This means that for any \( x_1 < x_2 \), we have \( g(x_1) \leq g(x_2) \). 2. **Defining the Composite Function:** - We define \( h(x) = g(f(x)) \). This means that \( h(x) \) takes the output of \( f(x) \) and applies the function \( g \) to it. 3. **Given Condition:** - We are given that \( h(0) = 0 \). This implies that \( g(f(0)) = 0 \). 4. **Analyzing \( f(0) \):** - Since \( f \) is non-increasing and defined on \( [0, \infty) \), the value \( f(0) \) must be some non-negative value (let's denote it as \( a \)). Thus, \( f(0) = a \) where \( a \geq 0 \). 5. **Applying the Condition:** - From \( h(0) = 0 \), we have \( g(a) = 0 \). Since \( g \) is non-decreasing, if \( g(a) = 0 \), then for any \( x \geq a \), \( g(x) \) must also be greater than or equal to 0. Therefore, \( g(x) \) cannot decrease below 0. 6. **Behavior of \( h(x) \):** - Since \( f \) is non-increasing, \( f(x) \) will either stay constant or decrease as \( x \) increases. This means that \( f(x) \leq f(0) = a \) for all \( x \geq 0 \). - Consequently, since \( g \) is non-decreasing and \( g(a) = 0 \), we have \( g(f(x)) \leq g(a) = 0 \) for all \( x \geq 0 \). 7. **Conclusion about \( h(x) \):** - Since \( h(x) = g(f(x)) \) is always less than or equal to 0 and starts at 0, the only possibility is that \( h(x) \) is constant and equal to 0 for all \( x \geq 0 \). 8. **Finding \( h(2020) \):** - Therefore, \( h(2020) = 0 \). ### Final Answer: \[ h(2020) = 0 \]
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MCGROW HILL PUBLICATION-SETS, RELATIONS AND FUNCTIONS-EXERCISE ( LEVEL 2 (SINGLE CORRECT ANSWER TYPE QUESTIONS ))
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