` cos theta - 4 sin theta = 1 implies sin theta + 4 cos theta = `

[(1 + cos theta + i sin theta) / (sin theta + i (1 + cos theta))] ^ (4) = cos n theta + i sin n theta

(cos theta + sin theta )/( cos theta - sin theta )-(cos theta - sin theta )/( cos theta + sin theta ) =

If (cos theta-4sin theta)=1 then (sin theta+4cos theta)=1)+-12)03 ) 24+-4

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

If cos theta -4 sin theta =1, then the value of (sin theta+4 cos theta) is-

4 sin theta * cos^(3) theta-4 cos theta * sin ^(3)theta= A) 4 cos theta B) cos 4 theta C) 4 sin theta D) sin 4 theta

(1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)