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If P(x)=ax^2+bx+c, Q(x)=-ax^2+dx+c where...

If `P(x)=ax^2+bx+c`, `Q(x)=-ax^2+dx+c` where `ac!=0` then `P(x).Q(x)=0` has

A

no real root

B

exactly two real roots

C

at least two real roots

D

none of these

Text Solution

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The correct Answer is:
C
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