If alpha!= beta but alpha^2 = 5alpha-3, ...

If `alpha!= beta` but `alpha^2 = 5alpha-3, beta^2 = 5beta - 3`, then find the equation whose roots are `alpha/beta and beta/alpha`.

A

`3 x^(2) - 25 x +3 = 0`

B

`x^(2) - 5x + 3 = 0`

C

`x^(2) + 5x - 3 =0`

D

`3x^(2) - 19x + 3 = 0`

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The correct Answer is:

D

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