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Product of roots of the equation x - sqr...

Product of roots of the equation `x - sqrt(3 x - 6) = 2` is

A

2

B

5

C

7

D

10

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The correct Answer is:
To find the product of the roots of the equation \( x - \sqrt{3x - 6} = 2 \), we will follow these steps: ### Step 1: Rearranging the Equation First, we rearrange the equation to isolate the square root: \[ x - 2 = \sqrt{3x - 6} \] **Hint:** Always isolate the square root when solving equations involving square roots. ### Step 2: Squaring Both Sides Next, we square both sides to eliminate the square root: \[ (x - 2)^2 = (\sqrt{3x - 6})^2 \] This simplifies to: \[ x^2 - 4x + 4 = 3x - 6 \] **Hint:** Squaring both sides is a common technique to eliminate square roots, but remember to check for extraneous solutions later. ### Step 3: Rearranging to Form a Quadratic Equation Now, we rearrange the equation to bring all terms to one side: \[ x^2 - 4x + 4 - 3x + 6 = 0 \] This simplifies to: \[ x^2 - 7x + 10 = 0 \] **Hint:** Always combine like terms carefully when rearranging equations. ### Step 4: Factoring the Quadratic Equation Next, we factor the quadratic equation: \[ x^2 - 7x + 10 = (x - 5)(x - 2) = 0 \] **Hint:** Look for two numbers that multiply to the constant term (10) and add to the coefficient of \( x \) (-7). ### Step 5: Finding the Roots Setting each factor to zero gives us the roots: 1. \( x - 5 = 0 \) → \( x = 5 \) 2. \( x - 2 = 0 \) → \( x = 2 \) **Hint:** Each factor gives a potential root; solve for \( x \) by setting each factor equal to zero. ### Step 6: Calculating the Product of the Roots The product of the roots is: \[ 5 \times 2 = 10 \] **Hint:** The product of the roots can also be found using the formula \( \frac{c}{a} \) from the quadratic equation \( ax^2 + bx + c = 0 \). ### Conclusion Thus, the product of the roots of the equation \( x - \sqrt{3x - 6} = 2 \) is \( \boxed{10} \).
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MCGROW HILL PUBLICATION-QUADRATIC EQUATIONS-Exercise ( Level 1 (single correct answer type questions))
  1. Two non-integer roots of (x^(2) - 5x)^(2) - 7 (x^(2) - 5x) + 6 = 0 are

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  2. The number of real roots of ((x - 1)/( x + 1))^(4) - 13 ((x - 1)/( x +...

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  3. The number of negative roots of 9^(x +2) - 6 (3^(x +1)) + 1 = 0 is

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  4. The number of roots of 81 ((2x - 5)/( 3x +1))^(4) - 45 ((2x - 5)/(3x ...

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  5. (x^2+3x+2)^2 - 8(x^2+3x) -4 =0

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  6. The number of roots of the equation sqrt((x)/(x - 3)) + sqrt((x - 3)/(...

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  7. 4(x-1/x)^2+8(x+1/x)=29 is

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  8. Irrational roots of the equaiton 2x^(4) + 9x^(3) + 8x^(2) + 9x + 2 = 0...

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  9. Sum of the roots of the equaiton 4 (x - (1)/(x))^(2) - 4 (x - (1)/(x)...

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  10. The number of irrational roots of the equation (x-1) (x-2) (3x-2) (...

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  11. Product of roots of the equation x - sqrt(3 x - 6) = 2 is

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  12. Number of roots of the equation 2sqrt(2x+1)=2x-1 is 0 (b) 1 (c) 2 (...

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  13. Product of roots of the equation sqrt(13 - x^(2)) = x + 5 is

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  14. The number of roots of the equation sqrt(x^2-4) -(x- 2) = sqrt(x^2 - 5...

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  15. The product of the roots of the equaiton sqrt(x^(2) - 4x + 3 ) + sqrt...

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  16. Suppose a and b satisfy the equations 18 a^(2) + 77 a + 2 = 0 and 2b^(...

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  17. Suppose alpha, beta are roots of x^(2)-7x+8=0, with alpha gt beta, the...

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  18. If alpha is a root of x^(4) + x^(2) - 1 = 0 , the value of (alpha^(6)...

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  19. Sum and product of all the roots of the equation (x^(2)-x-1)(x^(2)-x-2...

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  20. Suppose three distinct non-zero real numbers satisfy a^(2) (a + k) = b...

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