A particle starts moving from point (2, 10, 1). Displacement for the particle is `8hati - 2hatj + hatk` . The final coordinates of the particle is

A particle acted by constant forces 4 hati + hatj - 3 hatk and 3 hati + hatj - ahtk is displaced from the point hati + 2 hatj + 3 hatk to the point 5 hati + 4 hatj + hatk. The total work done by the forces is :

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

A uniform force of (3hati+hatj) N acts on a particle of mass 2kg. Hence, the particle is displaced from position (2hati+hatk) m to position (4hati+3hatj-hatk) m. The work done by the force on the particle is

A uniform force of (3hati+hatj) N acts on a particle of mass 2kg. Hence, the particle is displaced from position (2hati+hatk) m to position (4hati+3hatj-hatk) m. The work done by the force on the particle is

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m/s and moves in plane with a constant acceleration of (8hati + 2hatj)ms^(-2) . The y-coordinate of the particle in 2 sec is

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m/s and moves in plane with a constant acceleration of (8hati + 2hatj)ms^(-2) . The y-coordinate of the particle in 2 sec is

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m//s and moves in the x-y plane with a constant acceleration of (8.0hati + 2.0hatj) m s^-2 ,:- At what time is the x- coordinate of the particle 16 m? What is the y-coordinate of the particle at that time?