20 ml of 0.1 M solution of metal ion reacted with 20 ml to 0.1 M `SO_(2)` solution . `SO_(2)` reacted according to the equation `SO_(2) + 2H_(2)O rarr SO_(4)^(2-) + 4H^(+) + 2e^(-)`. If the oxidation no. of metal ion was `+ 3`, the new oxidation number of the metal would be `:`

In an experiment, 50 mL of 0.1 M solution off a metallic salt M(NO_(3)) reacted exactly with 25 mL of 0.1 M solution of NaSO_(3) in the reaction SO_(3)^(2-) is oxidized to SO_(4)^(2-) . If in the original salt oxidation number of the metal was 3, what would be the new oxidation number of metal?

In an experiment 50ml of 0.1(M) solution of a salt is reacted with 25ml of 0.1(M) solution of sodium sulphite. The half equation for the oxidation of sulphite ion is SO_(3)^(2-)(aq)+H_(2)O rarr SO_(4)^(2-)(aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal?

In an experiment, 50 mL of 0.1 M solution off a metallic salt M(NO_(3)) reacted exactly with 25 mL of 0.1 M solution of NaSO_(3) in the reaction SO_(3)^(2-) is oxidized to SO_(4)^(2-) . If in the original salt oxidation number fo the metal was 3, what would be the new oxidation number of metal?

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

In an experiment, 50 ml of 0.1 M solution of a salt reacted with 25 ml of 0.1 M solution of sodium sulphite. The half equation for the oxidation of sulphite ion : SO_(3(aq))H_2OrarrSO_(4(aq))^(2-)+2H_((aq))^+ If the oxidation number of the metal in the salt was 3, what would be the new oxidation number of the metal ?

50 mL of 0.1M solution of a salt reacted with 25 mL of 0.1M solution of sodium sulphite. The half reaction for the oxidation of sulphate ion is: SO_(3(aq.))^(2-)+H_(2)O_((l))rarrSO_(4(aq.))^(2-)+2H_(+(aq.))+2e If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal?

100mL of " 0.1 M NaOH" solution is titrated with 100mL of "0.5 M "H_(2)SO_(4) solution. The pH of the resulting solution is : ( For H_(2)SO_(4), K_(a1)=10^(-2))

100mL of " 0.1 M NaOH" solution is titrated with 100mL of "0.5 M "H_(2)SO_(4) solution. The pH of the resulting solution is : ( For H_(2)SO_(4), K_(a1)=10^(-2))

What volume of 0.34 M KOH is sufficient to react with 20 ml of 0.15M H_(2)SO_(4) solution ?