(x tan^(-1)x^(2))/(1+x^(4))

Evaluate : int(x cosec(tan^(-1)x^(2)))/(1+x^(4))dx

int x(e^(tan^(-1)x^(2)))/(x^(4)+1)dx equals

For real numbers alpha, beta, gamma and delta , if int((x^(2)-1)+tan^(-1)((x^(2)+1)/(x)))/((x^(4)+3x^(2)+1)tan^(-1)((x^(2)+1)/(x)))dx = alpha log_(e)(tan^(-1)((x^(2)+1)/(x)))+beta "tan"^(-1)((gamma(x^(2)-1))/(x))+delta tan ((x^(2)+1)/(x))+C where is an arbitrary constant, then the value of 10(alpha+betagamma+delta) is equal to........

Evaluate : int(2"x"dot"tan"^(-1)x^2)/(1+"x"^4)"dx"

f(x)=tan^(-1)x-(2)/(pi)(tan^(-1)x)^(2)+(4)/(pi^(2))(tan^(-1)x)^(3)-....oo, then the sum of integral values of a for which the equation f^(2)(x)+(sin^(-1)x)^(2)=a, possess solution,is:

Solve for x : tan^(-1)((x-2)/(x-1))+tan^(-1)((x+2)/(x+1))=pi/4

Solve for x : tan^(-1)((x-2)/(x-1))+tan^(-1)((x+2)/(x+1))=pi/4

Solve for x : tan^(-1)((x-2)/(x-1))+tan^(-1)((x+2)/(x+1))=pi/4

Solve for x : tan^(-1)((x-2)/(x-1))+tan^(-1)((x+2)/(x+1))=pi/4