Home
Class 12
PHYSICS
A screen is at distance D = 80 cm form a...

A screen is at distance `D = 80` cm form a diaphragm having two narrow slits `S_(1)` and `S_(2)` which are `d = 2` mm apart.
Slit `S_(1)` is covered by a transparent sheet of thickness
`t_(1) = 2.5 mu m` slit `S_(2)` is covered by another sheet of thikness
`t_(2) = 1.25 mu m` as shown if Fig. 2.52.
Both sheets are made of same material having refractive index `mu = 1.40`
Water is filled in the space between diaphragm and screen. Amondichromatic light beam of wavelength `lambda = 5000 Å` is incident normally on the diaphragm.
Assuming intensity of beam to be uniform, calculate ratio of intensity of C to maximum intensity of interference pattern obtained on the screen `(mu_(w) = 4//3)`

Promotional Banner

Similar Questions

Explore conceptually related problems

In YSDE, both slits are covered by transparent slab. Upper slit is covered by slab of R.I. 1.5 and thickness t and lower is covered by R.I. 4/ 3 and thickness 2t, then central maxima

Two slits S_(1) and S_(2) illuminated by a white light source give a white central maxima. A transparent sheet of refractive index 1.25 and thickness t_(1) is placed in front of S_(1) . Another transparent sheet of refractive index 1.50 and thickness t_(2) is placed in front of S_(2) . If central maxima is not effected, then ratio of the thickness of the two sheets will be :

Two slits S_(1) and S_(2) illuminated by a white light source give a white central maxima. A transparent sheet of refractive index 1.25 and thickness t_(1) is placed in front of S_(1) . Another transparent sheet of refractive index 1.50 and thickness t_(2) is placed in front of S_(2) . If central maxima is not effected, then ratio of the thickness of the two sheets will be :

A plane monochromatic light falls normally on a diaphragm with two narrow slits separated by a distance d = 2.5 mm. A fringe pattern is formed on the screen placed at D = 100 cm behind the diaphragm. If one of the slits is covered by a glass plate of thickness 10mu m , then distance by which these fringes will be shifted will be :

In young's double slit experiment, distance between the slit S_1 and S_2 is d and the distance between slit and screen is D . Then longest wavelength that will be missing on the screen in front of S_1 is

In young's double slit experiment, distance between the slit S_1 and S_2 is d and the distance between slit and screen is D . Then longest wavelength that will be missing on the screen in front of S_1 is

In a Young's d ouble slit experiment, a monochromatic light of wavelenght 600 nm is used. If the two slits are covered bt transparent sheets of thickness 0.132 mm and 0.1 mm of refractive index 1.5, then the number of fringes that will shift due to introdiction of the sheets are