Show that `A(-3,0)` lies on `x^(2)+y^(2) + 8x+ 12 y + 15 = 0` and find the other end of
diameter thorugh A.

Show that A(3,-1) lies on the circle x^(2) +_ y^(2) - 2x + 4y = 0 . Also find the other end of the diameter through A.

(i) Find the other end of the diameter of the circle x^(2)+y^(2)-8x-8y+27=0 if one endof it (2,3). (ii) Snow that A(3,-1) lies on the circle x^(2)+y^(2)-2x+4y=0 . Also find the other end of the diameter through A.

(i) Find the other end of the diameter of the circle x^(2)+y^(2)-8x-8y+27=0 if one endof it (2,3). (ii) Snow that A(3,-1) lies on the circle x^(2)+y^(2)-2x+4y=0 . Also find the other end of the diameter through A.

If (2,3,5) is one end of a diameter of the sphere x^(2) +y^(2) +z^(2)- 6x -12y -2z +20 =0 , find co-ordinates of the other end of the diameter

P(-9,-1) is a point on the circle x^2+y^(2)+4x+8y-38=0 . The equation to the tangent at the other end of the diameter thorugh P is

P(-9,-1) is a point on the circle x^2+y^(2)+4x+8y-38=0 . The equation to the tangent at the other end of the diameter thorugh P is

If one end a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3,4), then find the cordinate of the other end of the diameter.

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.