Two capacitors `C_(1)` and `C_(2)` in a circuite are joined as shown. If `V_(A)=V_(1),V_(B)=V_(2)`, the potemntial of point `P` is

Two capacitors C_(1) and C_(2) in a circuit are joined as shown. If V_(A)=V_(1),V_(B)=V_(2) , the potential of point P is

Two condensers C_(1) and C_(2) in a circuit are jhioned as shown in . The potential fo point A is V_1 and that of B is V_2 . The potential of point D will be

Two condensers C_(1) and C_(2) in a circuit are jhioned as shown in . The potential fo point A is V_1 and that of B is V_2 . The potential of point D will be

Two capacitors C_(1) and C_(2) are connected in a circuit as shown in figure. The potential difference (V_(A) - V_(B)) is

Four capacitors and two batteries are connected as shown in the diagram. If V_(a) and V_(b) denote the potentials of the points 'a' and 'b' then .

The circuit consists of resistors and ideal cells. I_(1) and I_(2) are current through branches indicated in the figure, V_(A) and V_(B) is the potential at points A and B on the circuit The value of V_(A) - V_(B) in volts is:

The circuit consists of resistors and ideal cells. I_(1) and I_(2) are current through branches indicated in the figure, V_(A) and V_(B) is the potential at points A and B on the circuit The value of V_(A) - V_(B) in volts is:

The p.d (V_(B)-V_(C) between two point from C to B

Two capacitors C_(1) and C_(2) are connected to a battery of 6 V as shown in Fig. Find the charge on each capacitor.