If `x = 3 cos theta - 2 cos^3 theta,y = 3 sin theta - 2 sin^3 theta`, then `dy/dx` is

x=3costheta-2cos^(3)theta, y = 3 sin theta- 2 sin^(3) theta

if x = "cos" theta - "cos" 2 theta, y = "sin" theta - "sin" 2 theta , then dy/dx is

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

Find dy/dx if : x= 3 cos theta - 2 cos^3 theta , y= 3 sin theta - 2 sin^3 theta

If x =3 cos theta -2 cos ^(3) theta, y=3sin theta -2 sin ^(3) theta ,then " at " theta =(pi)/(4),(dy)/(dx)

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =