यदि `theta = pi/8` है, तो `(2 cos theta + 1)^(10)` , `(2cos 2 theta-1)^(10) (2 cos theta - 1)^(10)` , `(2 cos 4 theta- 1)^(10)` का मान है ?

If theta=(pi)/(8) , then what is the value of (2cos theta+1)^(10)(2cos2theta-1)^(10)(2cos theta-1)^(10)(2cos4 theta-1)^(10) ?

If theta=(pi)/(8), then what is value of (2cos theta+1)^(10)(2cos2 theta-1)^(10)(2cos theta-1)^(10)(2cos4 theta-1)^(10)?(i)0(ii)1(iii)2(iv)4

The value (2cos theta-1)(2cos2 theta-1)(2cos4 theta-1)(2cos8 theta-1)=

(1+cos theta+i sin theta)^(10)+(1+cos theta-i sin theta)^(10)=

sin (40 + theta) * cos (10 + theta) -cos (40 + theta) sin (10 + theta) = (1) / (2)

If sin theta=(p^2-1)/(p^2+1) , then cos theta is equal to : यदि sin theta= (p^2-1)/(p^2+1) है, तो cos theta का मान है :

The value of (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 is: (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 का मान है :