" The solution of the differential equation "x log x(dy)/(dx)+y=2log x" is- "

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e ) is equal to :

Let y(x) be the solution of the differential equation ( x log x) (dy)/(dx) + y = 2x log x, ( x gt 1). then y (e) is equal to :

Let y(x) be the solution of the differential equation (x log x)(dy)/(dx)+y=2x log x,(x>=1) Then y(e) is equal to :(1)e(2)0(3)2(4)2e

The I.F. of the differential equation x log x (dy)/(dx) + 2y = log x is

find the solution of the following differential equation x log x(dy)/(dx)+y=2log x

Let y(x) be the solution of the differential equation . (x log x) (dy)/(dx) + y = 2x log x, (x ge 1) . Then y (e) is equal to

Find the general solution of the differential equation x log x*(dy)/(dx)+y=(2)/(x)*log x

The solution of the differential equation (dy)/(dx)= x log x is

The solution of the differential equation (dy)/(dx)= x log x is