[" 12.यदि "AD,BE" अौर "CF,Delta ABC" की माधियकाए है ,तो सिब्ध कीजिज "],[" बिन्न "quad vec AAD+BE+vec CF=0]

If AD, BE and CF be the median of a /_\ABC , prove that vec(AD)+vec(BE)+vec(CF) =0

If AD, BE and CF be the median of a /_\ABC , prove that vec(AD)+vec(BE)+vec(CF) =0

In an isosceles triangle ABC, AB=AC and AD is perpendicular to BC at D. If AD = 8 cm and perimeter of triangle ABC is 64cm, then the area of triangle ABC एक समद्विबाहु त्रिभुज ABC में, AB= AC और AD, BC पर लंबवत है। यदि AD =8 सेमी और ABC की परिधि 64 cm है, तो ABC का क्षेत्रफल है:

Let D, E and F be the middle points of the sides BC,CA and AB, respectively of a triangle ABC. Then prove that vec AD+vec BE+vec CF=vec 0

In triangle ABC AD, BE, CF are medians. If the area of the triangle DGC is 20cm^2 , then the area of triangle AGF + the area of triangle BGF is equal to: त्रिभुज ABC में, AD, BE और CF मध्यरेखा हैं और G त्रिभुज का केन्द्रक है। यदि त्रिभुज DGC का क्षेत्रफल 20cm^2 है, तो त्रिभुज AGF का क्षेत्रफल+ त्रिभुज BGF का क्षेत्रफल किसके बराबर है:

In Delta ABC and Delta DEF , AB = DE, AB|| DE , BC = EF and BC|| EF . Vertices A, B and C are joined to vertices D, E and F respectively (See fig.) Show that AD ||CF and AD=CF.

In Delta ABC and Delta DEF , AB = DE, AB|| DE , BC = EF and BC|| EF . Vertices A, B and C are joined to vertices D, E and F respectively (See fig.) Show that AD ||CF and AD=CF.

Three medians AD, BE and CF of Delta ABC intersect at G. The area of Delta ABC is 36 sq. cm. Then the area of Delta CGE is