NORMALITY|O.A AND R.A

Oxidising Agent and Reducing Agent || Determination OF O.A .and R.A. from Reaction || Determination OF O.A. and R.A. from Oxidation Number || Various Solved Class Question

A B C D IS A PARALLELOGRAM AND O is any point in its interior. Prove that: a r\ ( A O B)+\ a r\ ( C O D)=\ a r\ ( B O C)+\ a r( A O D) a r\ ( A O B)+a r\ (C O D)=1/2\ a r(^(gm)A B C D) Given: A parallelogram A B C D\ a n d\ O is a point in its interior. To Prove: a r\ (\ A O B)+\ a r( C O D)=a r\ ( B O C)+a r( A O D)

Application OF ON|| Strength OF Acid- Base|| Determination OF OA and RA|| Determination OF possible formula OF Compound|| Determination OF Equivalent Weight OF OA and RA

R-overset(O)overset(||)(C)-O-R'+R''OH overset(H^(o+))(hArr)R-overset(O)overset(||)(C)-O-R''+R'OH Above reaction is/an example of :

Consider the binary operations *:" "RxxR ->R and o:" "R" "xx" "R->R defined as a*b|a-b| and a" "o" "b" "=" "a , AA""""a ," "b in R . Show that * is commutative but not associative, o is associative but not commutative.

Reaction OF R-OH || R-X || R-O-R

A B C D is a parallelogram whose diagonals intersect at Odot If P is any point on B O , prove that: a r\ ( A D O)=A R\ ( C D O) a r\ (\ A B P)=\ a r\ (\ C B P)

In Fig. 9.25, diagonals AC and BD of quadrilateral ABCD intersect at O such that O B" "=" "O D . If A B" "=" "C D , then show that: (i) a r" "(D O C)" "=" "a r" "(A O B) (ii) a r" "(D C B)" "=" "a r" "(A C B) (iii) D A" "||" "C