" 4) "10y-25-:5

Work out the following divisions. (i) (10x - 25) -: 5 (ii) (10x - 25) -: (2x - 5) (iii) 10y(6y + 21) -: 5(2y + 7) (iv) 96abc(3a -12)(5b - 30) -: 144(a - 4)(b - 6)

Work out the following divisions. (i) (10x - 25) -: 5 (ii) (10x - 25) -: (2x - 5) (iii) 10y(6y + 21) -: 5(2y + 7) (iv) 96abc(3a -12)(5b - 30) -: 144(a - 4)(b - 6)

Solve 11(x - 5) + 10(y - 2) + 54 = 0 7(2x - 1) + 9 (3y - 1) = 25

Workout the following division: (10x-25):-5

The foci of the ellipse 9x^(2)+ 5(y^(2)-10y +25)=45 are

The equation to the locus of a point P for which the distance from P to (0,5) is double the distance from P to y -axis is 1) 3x^(2)+y^(2)+10y-25=0 2) 3x^(2)-y^(2)+10y+25=0 3) 3x^(2)-y^(2)+10y-25=0 4) 3x^(2)+y^(2)-10y-25=0

Find the polar of (1,-2) with respect of x^(2) + y^(2) - 10 x - 10y + 25 = 0