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" (ii) "a^(3)-b^(3)-1-3ab...

" (ii) "a^(3)-b^(3)-1-3ab

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11.Factorise :a^(2)+b^(2)+2ab+2ac+2bc) Factorise: a^(3)-b^(3)1+3ab

Factorise : a^(3)-b^(3)+1+3ab

If a + b + 1 = 0, then the value of (a^(3) + b^(3) +1 -3ab) is

If a+b+1=0 then what is the value of (a^(3)+b^(3)+1-3ab) ?

If a-b=1, then the value of a^(3)-b^(3)-3ab will be -3(b)-1(c)1(d)3

Prove that: (a-b)^(3)=a^(3)-b^(3)-3ab(a-b)

Resolve a^(3)-b^(3)+1+3ab into factors.