The enthalpy changes at 298 kJ in successive breaking of `O-H` bonds of water, are
`H_(2)O(g) rarr H(g)+OH(g),DeltaH=498kJ mol^(-1)`
`OH(g) rarr H(g)+O(g), DeltaH =428 kJ mol^(-1)`
The bond energy of the O-H bond is

The enthalpy changes at 298 K in successive breaking of O-H bonds of water, are H_(2)O(g) rarr H(g)+OH(g),DeltaH=498kJ mol^(-1) OH(g) rarr H(g)+O(g), DeltaH =428 kJ mol^(-1) The bond energy of the O-H bond is

The enthalpy changes at 25^(@)C in successive breaking of O - H bonds of water are : H_(2)O(g) rarr H(g) + OH(g) Delta H = 498 kJ mol^(-1) OH(g) rarr H(g) + O(g) Delta H = 428 kJ mol^(-1) The bond enthalpy of the O-H bond is :

The bond dissociation energies of two O-H bond in water are: H_2O(g)rarr H(g)+OH(g), Delta H=497.8 KJ mol^(-1) OH(g)rarr H(g)+O(g), Delta H=428.5 KJ mol^(-1) bond energy of O-H bond is

Dissociation of water takes place in two steps : H_(2)OrarrH+OH," "DeltaH=+497.8kJ OH rarr H+O," "DeltaH=428.5kJ Water is the bond energy of O-H bond ?

H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g) DeltaH =- 242 kJ mol^(-1) Bond energy of H_(2) and O_(2) is 436 and 500 kJ mol^(-1) , respectively. What is bond energy of O-H bond?