The wing span of an aeroplane is 36 m. if the plane is flying at `400kmh^(-1)`, the emf induced between the wings tips is (Assume `V=4xx10^(-5)T`)

The wing span of an aeroplane is 40m. The plane is flying horizontally due north at 360 km/h. What is the potential difference developed between the wing-tips if the horizontla component of the Earth's magnetic field B_(h) = 3.2 xx 10^(-5) T and the angle of dip at the place is 60^(@) ?

The wing span of an aeroplane is 20 m. It is flying in a field, where the vertical component of magnetic field of earth is 5 xx 10^(-5) tesla, with velocity 360 km//h . The potential difference produced between the blades will be

The wing span of an aeroplane is 20 metre. It is flying in a field, where the verticle component of magnetic field of earth is 5xx10^(-5) tesla, with velocity 360 km//h . The potential difference produced between the blades will be

The wing span of an aeroplane is 20 metre. It is flying in a field, where the verticle component of magnetic field of earth is 5xx10^(-5) tesla, with velocity 360 km//h . The potential difference produced between the blades will be

The distance between the two end-points of the wings of an aeroplane is 5 m and the aeroplane is flying parallel to earth's surface with a velocity of 360 km h^(-1) . If the geomagnetic intensity is 4xx10^(-4)Wb . m^(-2) and the angle of dip at that place is 30^(@) , determine the emf induced between the two end-points of the wings.

The distance between the extremities of the two wings of an aeroplane is 30m. It is flying horizontally with a velocity of 1080km .h^(-1) . The vertical component of earth's magnetic field in that region is 4.5xx10^(-5)T . Find the emf induced across the extremities of the two wings.

In northern hemisphere, an airplane flies with a speed of 1000 km hr^(-1) towards east at constant height. Calculate the emf induced between the tips of the wings 50 m apart. The vertical component of Earth's magnetic field is 2 xx 10^(-5) T .