(16^(-1/5))^(5/2)

Simplify each of the following: (i) (16)^(1/5)xx(2)^(1/5) (ii) (243)^(1/ 4)/(3)^(1/ 4)

Simplify each of the following: (i) (16)^((1)/(5))xx(2)^((1)/(5)) (ii) ((243)^((1)/(4)))/((3)^((1)/(4)))

(16^(-1)xx5^(3))/(2^(-4))

If the surm of the first ten terms of the series,(1(3)/(5))^(2)+(2(2)/(5))^(2)+(3(1)/(5))^(2)+4^(2)+(4(4)/(5))^(2)+ is (16)/(5)m, then m is equal to

A B C is an isosceles triangle. If the coordinates of the base are B(1,3) and C(-2,7) , the coordinates of vertex A can be (1,6) (b) (-1/2,5) (5/6,6) (d) none of these

Evaluate (16)^(5/2) .

Let S_(n)=1.5+2.5^(2)+3.5^(3)+...+n.5^(n)=(1)/(16)[(4n-1)5^(a)+b] then