Two force vectors each having magnitude 6N are oriented as `30^(@)` from positive of x-axis and other at `90^(@)` with the same axis. Find out their magnitude along with position from positive of x-axis :-

A vector lying in x-y plane has a magnitude 3, and makes an angle 30^(@) with the x-axis. Find its components along the two axes.

A vector lying in x-y plane has a magnitude 3, and makes an angle 30^(@) with the x-axis. Find its components along the two axes.

Vector vecA of magnitude 4 units is directed along the positive x-axis. Another vector vecB of magnitude 3 units lies in the x-y plane and is directed along 30^(@) with the positive x-axis is as shown in figure. The magnitude of dot product vecA.vecB is:

A vector has a magnitudes of 12. What its tail is at the origin it lies between the positive x axis and the negative y axis and makes an angles of 30^(@) with x axis . Its y component is :

vector veca lies in the xy plane, has a magnitude of 18 units, and points in a direction 250^(@) from the positive direction of the x axis. Also, vector vecb has a magnitude of 12 units and points in the positive direction of the z axis. What is the vector product vecc=vecaxx vecb ?

The force acting on a particle makes an angle of 60^(@) with the positive x-axis. If the magnitude of the force is 10N what are its x and y-components?

Two vectors a and b have equal magni-tudes of 12 units. These vectors are making angles 30° and 120° with the x axis respectively. Their sum is r. Find the magnitude and the angle r makes with the +x axis.

A vector of magnitude 13 makes an angle 65.37^(@) with the x-axis . What is its component along positive y-axis ?