A string is rigidly tied at two ends and its equation of vibration is given by `y=sin2pix.cos2pit`. Then minimum length of string is

A string is rigidly tied at two ends and its equation of vibration is given by y=cos 2pix. Then minimum length of string is

A string is rigidly tied at two ends and its equation of vibration is given by y = cos2 pi tsin2 pi x . Then minimum length of string is

A string is rigidly tied at two ends and its equation of vibration is given by y = cos(2 pi t)sin(2 pi x) . Then minimum length of string is

A vibrating string is tied at its two ends. The equation of the wave produced on the string is given by y= cos (2 pi t) sin (2pi x) What is the lenghts of the string,f it is in the fundamental node of vibration ?

The equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y=2cm sin[(0.6cm^-1)x]cos[(500pis^-1)t] . The length of the string is

The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :

The equation for the vibration of a string fixed at both ends vibrating in its second harmonic is given by y=2sin(0.3cm^(-1))xcos((500pis^(-1))t)cm . The length of the string is :