Velocity of a particle at any time t is `v=(2 hati+2t hatj) m//s.` Find acceleration and displacement of particle at `t=1s.` Can we apply `v=u+at` or not?

Velocity of a particle at time t=0 is 2 hati m/s. A constant acceleration of 2 m/s^2 acts on the particle for 2 s at an angle of 60^@ with its initial velocity. Find the magnitude of velocity and displacement of particle at the end of t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between t=2 to t=4 sec.

Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between t=2 to t=4 sec.

Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between t=2 to t=4 sec.

Acceleration of a particle at any time t is veca=(2thati+3t^(2)hatj)m//s^(2) .If initially particle is at rest, find the velocity of the particle at time t=2s