If 2^7 cos^3 theta sin^5 theta = a sin 8...

If `2^7 cos^3 theta sin^5 theta = a sin 8theta - bsin 6theta + csin 4theta + d sin2theta` and `theta` is real, then the value of a+b+c+d must be

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If 2^(7)cos^(3)theta sin^(5)theta=a sin8 theta-b sin6 theta+c sin4 theta+d sin2 theta and theta is real,then the value of a+b+c+d must be

If sin 6theta = sin 4theta - sin 2theta , then theta =

( sin 2 theta + 2 sin 4 theta + sin 6 theta )/(sin 4 theta + 2 sin 6 theta + sin 8 theta ) =

lf 5 cos theta=7 sin theta , find the value of ( sin theta + cos theta)/(2 sin theta -3 cos theta) .

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)

(sin5 theta-2sin3 theta + sin theta) / (cos5 theta-cos theta) = tan theta

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)=