For a fixed incident light ray, if the mirror be rotated through and angle `theta` (about an axis which lies in the plane of mirror and perpendicular to the plane of incidence), show that the reflected ray turns through an angle 2`theta` in same sense.

A plane mirror reflecting a ray of incident light is rotated through an angle q about an axis through the point of incidence in the plane of the mirror perpendicular to the plane of incidence, then (1) The reflected ray rotates through an angle 2q (2) The incident ray is fixed (3) The reflected ray does not rotate (4) The reflected ray rotates through an angle q

A plane mirror reflecting a ray of incident light is rotated through an angle q about an axis through the point of incidence in the plane of the mirror perpendicular to the plane of incidence, then (1) The reflected ray rotates through an angle 2q (2) The incident ray is fixed (3) The reflected ray does not rotate (4) The reflected ray rotates through an angle q

A plane mirror, reflecting a ray of incident light, is rotated through an angle theta about an axis through the point of incidence in the plane of the mirror perpendicular to the plane of incidence, then

I is a ray incident on a plane mirror. Keeping the incident ray fixed, the mirror is rotated by an angle theta about an axis passing through A perpendicular to the plane of the Fig. show that the refracted ray rotates through an angle 2theta . Does your answer differ if the mirror is rotated about an axis passing through B?

A plane mirror reflecting a ray of incident light is rotated through an angle of 30^@ about an axis through the point of incidence in the plane of the mirror and perpendicular to the plane of incidence then

When a plane mirror is rotated through an angle theta , then the reflected ray turns through the angle 2theta , then the size of the image.

When a plane mirror is rotated through an angle theta then the reflected ray turns through the angle 2 theta then the size of the image