AX and DY are altitudes of two similar triangle `DeltaABC` and `DeltaDEF`. Prove that `AX:DY=AB:DE`.

AX and DY are altitudes of two similar triangles Delta ABC and Delta DEF . Prove that AX : DY = AB : DE.

AX and DY are altitudes of two similar triangles Delta ABC and Delta DEF . Prove that AX : DY = AB : DE.

AX and DY are altitudes of two similar triangles Delta ABC and Delta DEF . Prove that AX : DY = AB : DE.

CM and RN are respectively the medians of similar triangle DeltaABC and DeltaPQR . Prove that (CM)/(RN)=(AB)/(PQ)

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

DeltaABC and DeltaDEF are two similar triangle and the primeters of DeltaABC and DeltaDEF are 30 cm and 18 cm respectively . If the length of DE = 36 cm , then length of AB is

DeltaABC and DeltaDEF are equilateral triangles, A(DeltaABC) : A(DeltaDEF)= 1 :2 . If AB=4 then what is the length of DE ?

DeltaABC and DeltaDEF are equilateral triangles, A(DeltaABC) : A(DeltaDEF)= 1 :2 . If AB=4 then what is the length of DE ?

In the adjoining figure D, E and F are the mid-points of the sides BC, CA and AB of the equilateral DeltaABC. Prove that DeltaDEF is also an equilateral triangle.

In the adjoining figure D, E and F are the mid-points of the sides BC, CA and AB of the equilateral DeltaABC. Prove that DeltaDEF is also an equilateral triangle.