A particle of charge q and mass m is subjected to an electric field `E=E_(0)(1-ax^(2))` in the x - direction, where a and `E_(0)` are constants. Initially the particle was at rest at x = 0. Other than the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is :

A charged particle of chage q released in electric field E= E_0(1-ax^2) from origin. find position when its kinetic energy again becomes zero.

A charged particle of chage q released in electric field E= E_0(1-ax^2) from origin. find position when its kinetic energy again becomes zero.

A particle of mass 'm' is at rest the origin at time t =0. It is subjected to a force F(t) = F_(0)e^("bt") in the X-direction

A particle with specific charge q//m moves rectilinerarly due to an electric field E = E_(0) - ax , where a is a positive constant, x is the distance from the point where the particle was initially at rest. Find: (a) the distance covered by the particle till the moment it came to a standstill, (b) the acceleration of the particle at that moment.

A particle of charge q and mass m moves rectilinearly under the action of an electric field E= alpha- beta x . Here, alpha and beta are positive constants and x is the distance from the point where the particle was initially at rest. Then: (1) the motion of the particle is oscillatory with amplitude (alpha)/(beta) (2) the mean position of the particles is at x= (alpha)/(beta) (3) the maximum acceleration of the particle is (q alpha)/(m) (4) All 1, 2 and 3

A particle of mass m is subjected to a force vecF=F_(0)[cos (t)hati+sin(1)hatj] . If initially (t=0) the particle was at rest, the kinetic energy of the particle as a function of time is given by: