sum_(r=1)^(n)(r^(2)+1)(r!)=

sum_(r=1)^(n) r^(2)-sum_(r=1)^(n) sum_(r=1)^(n) is equal to

sum_(r=1)^(n) r^(2)-sum_(r=1)^(n) sum_(r=1)^(n) is equal to

sum_(r=1)^(n)(r)/(2^(r))=2-((1)/(2))^(2)(n+2)

If sum_(r=1)^(n) r(sqrt(10))/(3)sum_(r=1)^(n)r^(2),sum_(r=1)^(n) r^(3) are in G.P., then the value of n, is

If sum_(r=1)^(n) r(sqrt(10))/(3)sum_(r=1)^(n)r^(2),sum_(r=1)^(n) r^(3) are in G.P., then the value of n, is

If sum_(r=1)^(n)r(r+1)(2r+3)=an^(4)+bn^(3)+cn^(2)+dn+e , then.

If sum_(r=1)^(n)r(r+1)+sum_(r=1)^(n)(r+1)(r+2)=(n(an^(2)+bn+c))/(3),(a,b,cinN) then

If S_(1)= sum_(r=1)^(n) r , S_(2) = sum_(r=1)^(n) r^(2),S_(3) = sum_(r=1)^(n)r^(3) then : lim_(n to oo ) (S_(1)(1+(S_(8))/8))/((S_(2))^(2)) =

If sum_(r=1)^(n)r(r+1)+sum_(r=1)^(n)(r+1)(r+2)=(n(an^(2)+bn+c))/(3),(a,b,cinN) then (A) a + b + c = 24 (B) 2a + b - c = 0 (C) a - b + c= 6 (D) ab + bc + ca = 11