Pressure and volume of a gas changes from `(p_0V_0)` to `(p_0/4, 2V_0)` in a process `pV^2=` constant. Find work done by the gas in the given process.

For a thermodynamic system the pressure, volume and temperature are related as new gas law given as P=(alphaT^2)/V Here alpha is a constant. Find the work done by the system in this process when pressure remains constant and its temperature changes from T_0 to 2 T_0 .

The internal energy of a gas is given by U=2pV . It expands from V_0 to 2V_0 against a constant pressure p_0 . The heat absorbed by the gas in the process is

The internal energy of a gas is given by U=2pV . It expands from V_0 to 2V_0 against a constant pressure p_0 . The heat absorbed by the gas in the process is

The internal energy of a gas is given by U=2pV . It expands from V_0 to 2V_0 against a constant pressure p_0 . The heat absorbed by the gas in the process is

The internal energy of a gas is given by U = 3 pV. It expands from V_(0) to 2V_(0) against a constant pressure p_(0) . The heat absorbed by the gas in the process is

The internal energy of a gas is given by U = 3 pV. It expands from V_(0) to 2V_(0) against a constant pressure p_(0) . The heat absorbed by the gas in the process is

An ideal gas is taken through a thermodynamic cycle ABCDA. In state A pressure and volume are P_(0) and V_(0) respectively. During the process A rarr B , work done by the gas is zero and its temperature increases two fold. During the process B rarr C , internal energy of the gas remains constant but work done by it is W_(BC) = – P_(0)V_(0) ln2 . In the process C rarr D , the temperature decreases by 50% while the volume does not change. In the process D rarr A the temperature of the gas does not change. (a) Draw pressure – volume (P–V) and pressure – density (P – rho) graph for the cyclic process. (b) Calculate work done on the gas during the cycle.

The internal energy of a gas is given by U= 5 + 2PV . It expands from V_(0) to 2V_(0) against a constant pressure P_(0) . The heat absorbed by the gas in the process is :-

The internal energy of a gas is given by U= 5 + 2PV . It expands from V_(0) to 2V_(0) against a constant pressure P_(0) . The heat absorbed by the gas in the process is :-