The displacement of a particle executing `SHM` at any time `t` (Seconds) is `x =0.01sin 100pi (t = 0.005)` then its time period will be

The displacement of a particle executing S.H.M is given by x= 0.01 sin 100pi (t + 0.05) . The time period is

The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

Displacement of a particle executing SHM s x= 10 ( cos pi t + sin pi t) . Its maximum speed is

Displacement of a particle executing SHM s x= 10 ( cos pi t + sin pi t) . Its maximum speed is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle performing a S.H.M. is given by x=0.5 "sin" 100 pi (t + 0.05) , where x is in metres and t is in second. Its periodic time in second is

The displacement of a particle executing SHM is given by y=0.2sin50pi(t+0.01) metre Calculate the amplitude,t he period, maximum velocity and the displacement at the start of the motion.

The displacement of a particle executing a S.h.M. at any ins"tan"t t is x=4 "sin" (2pi t) . The acceleration produced in the particle is given by