[" 37.In a "Delta ABC" ."],[" i) "quad " The sides "AB" and "AC" are produced to "P],[" and "Q" respectively.If the bisectors of "],[/_PBC" and "/_QCB" intersect at A point "O],[" Prove that "/_BOC=90^(@)-(1)/(2)/_A]

The sides AB and AC of a Delta ABC are produced to P and Q respectively.If the bisectors of /_PBC and /_QCB ; Then /_BOC=90^(@)-(1)/(2)/_A

The sides AB and AC of ABC are product to P and Q respectively.the bisectors of exterior angles at B and C of ABC meet at O( fig..19) prove that /_BOC=90^(@)-(1)/(2)/_A

In figure, sides AB and AC of a Delta ABC are produced to P and Q, respectively. The bisectors of lt PBC and lt QCB intersect at O. Tnen. ltBOC is equal to

The sides AB and AC of ABC have been produced to D and E reapectively. The bisectors of /_CBD and /_BCE meet at O. If /_A=50^(@) , find /_BOC .

In Fig. 6.38, the sides AB and AC of ABC are produced to points E and D respectively. If bisectors BO and CO of CBE and BCD respectively meet at point O, then prove that /_B O C=90o-1/2/_B A C .

In the adjacent figure the sides AB and AC of Delta ABC are produced to points E and D respectively. If bisectors BO and CO of angleCBE and angleBCD respectively meet at point O, then prove that angleBOC = 90^(@)-(1)/(2) angleBAC .

In the adjacent figure the sides AB and AC of Delta ABC are produced to points E and D respectively. If bisectors BO and CO of angleCBE and angleBCD respectively meet at point O, then prove that angleBOC = 90^(@)-(1)/(2) angleBAC .

In the adjacent figure the sides AB and AC of Delta ABC are produced to points E and D respectively. If bisectors BO and CO of angleCBE and angleBCD respectively meet at point O, then prove that angleBOC = 90^(@)-(1)/(2) angleBAC .

In the adjacent figure the sides AB and AC of Delta ABC are produced to points E and D respectively. If bisectors BO and CO of angleCBE and angleBCD respectively meet at point O, then prove that angleBOC = 90^(@)-(1)/(2) angleBAC .