[" The wavelength of "H_(beta)" spectral line of Balmer series is "4860A" then find out the wavelength of "],[H_(alpha)" spectral line of the same series."]

The wavelength of H_(alpha) line in Balmer series is

The wavelength of the first spectral line of the Lyman series is lambda then the wavelength of the first spectral line of the Paschen series is ......... lambda

The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. If the wavelength of the spectral line in the Balmer series of singly-ionized helium atom is 1215 when electron jumps from n_2 to n_1 , then n_2 and n_1 , are

The wavelength of H_(alpha) line is Balmer series is 6563 Å. Compute the wavelength of H_(beta) line of Balmer series.