A series RLC circuit has the following values `R=20Omega`, `X_(L)=10Omega`. `E=50V`(rms) at `omega=400` rad/s. Current `2A` leads the applied voltage. The value of the capacitative reactance `X_(C )` is

In a series L-C-R circuit X_(L)350 Omega, X_(C)=200 Omega and R = 150 Omega .

In a series circuit R=300Omega, L=0.9H, C=2.0 mu F, omega=1000 rad/s. The imedance of the circuit is

A series R-L-C circuit has R = 100 ohm. L = 0.2 mH and C = (1)/(2) mu F . The applied voltage V = 20 sin omega t . Then When the currentsd lags the applied voltage by 45^(@) , the value of omega is approximately

In a given series LCR circuit R=4Omega, X_(L)=5Omega and X_(C)=8Omega , the current

In a given series LCR circuit R=4Omega, X_(L)=5Omega and X_(C)=8Omega , the current

In an AC series circuit, R = 10 Omega, X_L=20Omega and XC=10Omega .Then, choose the correct options

In an AC series circuit, R = 10 Omega, X_L=20Omega and XC=10Omega .Then, choose the correct options

In a series A.C. circuit , R=100Omega , X_(L)=300Omega and X_(C )=200Omega . The phase difference between the applied e.m.f. and the current will be