Give the solution of `x" sin"^(2)(y)/(x)dx =y dx -x dy` which passes through the point `(1, (pi)/(4))`.

The solution of sin^(-1)((dy)/(dx)) = y + x is

Find the equation of a curve whoise gradient is (dy)/(dx)=(y)/(x)-"cos"^(2)(y)/(x) , where x gt 0, y gt 0 and which passes through the point (1, (pi)/(4)) .

The solution curve of the differential equation, (1+e^(-x))(1+y^(2))(dy)/(dx)=y^(2) , which passes through the point (0,1), is:

The equation of the curve whose slope is given by (dy)/(dx)=(2y)/x ; x >0,\ y >0 and which passes through the point (1,1) is

The solution of cos y + (x sin y-1) (dy)/(dx) = 0 is

A curve y=y(x) is a solution of (x tan((y)/(x))-y sec^(2)((y)/(x)))dx+x sec^(2)((y)/(x))dy=0 passing through the point (1 ,(pi)/(4)) is

Solution of cos x (dy)/(dx) + y sin x = 1 is

The solution of the differential equation (dy)/(dx) = (y ^(2))/(x) passing through the point (1,-1) is

A solution curve of the differential equation (x^(2)+xy+4x+2y+4)(dy)/(dx)-y^(2)=0, x gt0 , passes through the point (1, 3). Then the solution curve-

Solution of cos x ( dy)/( dx) + y sin x=1 is :