Two identical pendulums oscillate with a constant phase difference `(pi)/(4)` and same amplitude. If the maximum velocity of one is v, the maximum velocity of the other will be.

Two pendulums oscillates with a constant phase difference of 90^(@) and same amplitude. The maximum velocity of one pendulum is v, then the maximum velocity of the other pendulum will be

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2s, then its maximum velocity is………..

For a particle in S.H.M. if the maximum acceleration is a and maximum velocity is v then amplitude is

The velocity of simple pendulum is maximum at

A sine wave has an amplitude A and wavelength lambda . Let V be the wave velocity and v be the maximum velocity of a particle in the medium. Then

A sine wave has an amplitude A and wavelength lambda . Let V be the wave velocity and v be the maximum velocity of a particle in the medium. Then